Optimal. Leaf size=101 \[ \frac{2 a^2 \left (a+b x^4\right )^{15/4}}{5 b^5}-\frac{4 a^3 \left (a+b x^4\right )^{11/4}}{11 b^5}+\frac{a^4 \left (a+b x^4\right )^{7/4}}{7 b^5}+\frac{\left (a+b x^4\right )^{23/4}}{23 b^5}-\frac{4 a \left (a+b x^4\right )^{19/4}}{19 b^5} \]
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Rubi [A] time = 0.0569821, antiderivative size = 101, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 15, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.133, Rules used = {266, 43} \[ \frac{2 a^2 \left (a+b x^4\right )^{15/4}}{5 b^5}-\frac{4 a^3 \left (a+b x^4\right )^{11/4}}{11 b^5}+\frac{a^4 \left (a+b x^4\right )^{7/4}}{7 b^5}+\frac{\left (a+b x^4\right )^{23/4}}{23 b^5}-\frac{4 a \left (a+b x^4\right )^{19/4}}{19 b^5} \]
Antiderivative was successfully verified.
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Rule 266
Rule 43
Rubi steps
\begin{align*} \int x^{19} \left (a+b x^4\right )^{3/4} \, dx &=\frac{1}{4} \operatorname{Subst}\left (\int x^4 (a+b x)^{3/4} \, dx,x,x^4\right )\\ &=\frac{1}{4} \operatorname{Subst}\left (\int \left (\frac{a^4 (a+b x)^{3/4}}{b^4}-\frac{4 a^3 (a+b x)^{7/4}}{b^4}+\frac{6 a^2 (a+b x)^{11/4}}{b^4}-\frac{4 a (a+b x)^{15/4}}{b^4}+\frac{(a+b x)^{19/4}}{b^4}\right ) \, dx,x,x^4\right )\\ &=\frac{a^4 \left (a+b x^4\right )^{7/4}}{7 b^5}-\frac{4 a^3 \left (a+b x^4\right )^{11/4}}{11 b^5}+\frac{2 a^2 \left (a+b x^4\right )^{15/4}}{5 b^5}-\frac{4 a \left (a+b x^4\right )^{19/4}}{19 b^5}+\frac{\left (a+b x^4\right )^{23/4}}{23 b^5}\\ \end{align*}
Mathematica [A] time = 0.0308585, size = 61, normalized size = 0.6 \[ \frac{\left (a+b x^4\right )^{7/4} \left (4928 a^2 b^2 x^8-3584 a^3 b x^4+2048 a^4-6160 a b^3 x^{12}+7315 b^4 x^{16}\right )}{168245 b^5} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.007, size = 58, normalized size = 0.6 \begin{align*}{\frac{7315\,{x}^{16}{b}^{4}-6160\,a{x}^{12}{b}^{3}+4928\,{a}^{2}{x}^{8}{b}^{2}-3584\,{a}^{3}{x}^{4}b+2048\,{a}^{4}}{168245\,{b}^{5}} \left ( b{x}^{4}+a \right ) ^{{\frac{7}{4}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.95501, size = 109, normalized size = 1.08 \begin{align*} \frac{{\left (b x^{4} + a\right )}^{\frac{23}{4}}}{23 \, b^{5}} - \frac{4 \,{\left (b x^{4} + a\right )}^{\frac{19}{4}} a}{19 \, b^{5}} + \frac{2 \,{\left (b x^{4} + a\right )}^{\frac{15}{4}} a^{2}}{5 \, b^{5}} - \frac{4 \,{\left (b x^{4} + a\right )}^{\frac{11}{4}} a^{3}}{11 \, b^{5}} + \frac{{\left (b x^{4} + a\right )}^{\frac{7}{4}} a^{4}}{7 \, b^{5}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.70675, size = 180, normalized size = 1.78 \begin{align*} \frac{{\left (7315 \, b^{5} x^{20} + 1155 \, a b^{4} x^{16} - 1232 \, a^{2} b^{3} x^{12} + 1344 \, a^{3} b^{2} x^{8} - 1536 \, a^{4} b x^{4} + 2048 \, a^{5}\right )}{\left (b x^{4} + a\right )}^{\frac{3}{4}}}{168245 \, b^{5}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 47.7124, size = 136, normalized size = 1.35 \begin{align*} \begin{cases} \frac{2048 a^{5} \left (a + b x^{4}\right )^{\frac{3}{4}}}{168245 b^{5}} - \frac{1536 a^{4} x^{4} \left (a + b x^{4}\right )^{\frac{3}{4}}}{168245 b^{4}} + \frac{192 a^{3} x^{8} \left (a + b x^{4}\right )^{\frac{3}{4}}}{24035 b^{3}} - \frac{16 a^{2} x^{12} \left (a + b x^{4}\right )^{\frac{3}{4}}}{2185 b^{2}} + \frac{3 a x^{16} \left (a + b x^{4}\right )^{\frac{3}{4}}}{437 b} + \frac{x^{20} \left (a + b x^{4}\right )^{\frac{3}{4}}}{23} & \text{for}\: b \neq 0 \\\frac{a^{\frac{3}{4}} x^{20}}{20} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.12623, size = 96, normalized size = 0.95 \begin{align*} \frac{7315 \,{\left (b x^{4} + a\right )}^{\frac{23}{4}} - 35420 \,{\left (b x^{4} + a\right )}^{\frac{19}{4}} a + 67298 \,{\left (b x^{4} + a\right )}^{\frac{15}{4}} a^{2} - 61180 \,{\left (b x^{4} + a\right )}^{\frac{11}{4}} a^{3} + 24035 \,{\left (b x^{4} + a\right )}^{\frac{7}{4}} a^{4}}{168245 \, b^{5}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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